Arrays January 01 ,2026

Search an Element in an Array (Linear Search)

Problem Statement

Given an array of integers and a target value, the task is to search whether the target element exists in the array.
If it exists, return its index position; otherwise, indicate that the element is not present.

This searching technique is known as Linear Search, because elements are checked one by one in a linear manner.

Why This Problem Matters

Linear Search is:

  • The simplest searching algorithm
  • A foundation for understanding advanced searching techniques
  • Useful when:
    • The array is unsorted
    • The dataset size is small
    • No preprocessing is allowed

Many interview problems start with linear search before optimizing to binary search or hashing.

Input and Output Format

Input

arr = [10, 20, 30, 40, 50]
target = 30

Output

Element found at index 2

If element does not exist:

Element not found

The idea is very straightforward:

  • Start from the first element
  • Compare each element with the target
  • Stop when:
    • The element is found
    • The array ends

Step-by-Step Algorithm

  1. Start from index 0
  2. Compare arr[i] with target
  3. If equal, return index i
  4. If end of array is reached and no match is found, return -1

Pseudocode

for i from 0 to n-1:
    if arr[i] == target:
        return i
return -1

Dry Run Example

Array:  [10, 20, 30, 40, 50]
Target: 30

i = 0 → 10 ≠ 30
i = 1 → 20 ≠ 30
i = 2 → 30 = 30 → FOUND

Result: Index 2

Time and Space Complexity

MetricValue
Time ComplexityO(n)
Best CaseO(1)
Worst CaseO(n)
Space ComplexityO(1)
Linear Search – Searching & Sorting – Data Structures & Algorithms

Language-wise Implementation

C Implementation

#include 

int main() {
    int arr[] = {10, 20, 30, 40, 50};
    int target = 30;
    int n = sizeof(arr) / sizeof(arr[0]);
    int foundIndex = -1;

    for(int i = 0; i < n; i++) {
        if(arr[i] == target) {
            foundIndex = i;
            break;
        }
    }

    if(foundIndex != -1)
        printf("Element found at index %d", foundIndex);
    else
        printf("Element not found");

    return 0;
}

Output

Element found at index 2

C++ Implementation

#include 
using namespace std;

int main() {
    int arr[] = {10, 20, 30, 40, 50};
    int target = 30;
    int n = sizeof(arr) / sizeof(arr[0]);

    for(int i = 0; i < n; i++) {
        if(arr[i] == target) {
            cout << "Element found at index " << i;
            return 0;
        }
    }

    cout << "Element not found";
    return 0;
}

Output

Element found at index 2

Java Implementation

public class Main {
    public static void main(String[] args) {
        int[] arr = {10, 20, 30, 40, 50};
        int target = 30;
        int index = -1;

        for(int i = 0; i < arr.length; i++) {
            if(arr[i] == target) {
                index = i;
                break;
            }
        }

        if(index != -1)
            System.out.println("Element found at index " + index);
        else
            System.out.println("Element not found");
    }
}

Output

Element found at index 2

Python Implementation

arr = [10, 20, 30, 40, 50]
target = 30
index = -1

for i in range(len(arr)):
    if arr[i] == target:
        index = i
        break

if index != -1:
    print("Element found at index", index)
else:
    print("Element not found")

Output

Element found at index 2

C# Implementation

using System;

class Program {
    static void Main() {
        int[] arr = {10, 20, 30, 40, 50};
        int target = 30;
        int index = -1;

        for(int i = 0; i < arr.Length; i++) {
            if(arr[i] == target) {
                index = i;
                break;
            }
        }

        if(index != -1)
            Console.WriteLine("Element found at index " + index);
        else
            Console.WriteLine("Element not found");
    }
}

Output

Element found at index 2

JavaScript Implementation

let arr = [10, 20, 30, 40, 50];
let target = 30;
let index = -1;

for (let i = 0; i < arr.length; i++) {
    if (arr[i] === target) {
        index = i;
        break;
    }
}

if (index !== -1)
    console.log("Element found at index", index);
else
    console.log("Element not found");

Output

Element found at index 2

Edge Cases to Consider

  1. Element at first index
  2. Element at last index
  3. Element not present
  4. Array with duplicate elements
  5. Empty array

Common Mistakes

  • Forgetting to break after finding the element
  • Returning incorrect index
  • Not handling empty array
  • Confusing value with index

Interview Notes

Interviewers evaluate:

  • Correct traversal logic
  • Early termination using break
  • Time complexity awareness

Follow-up questions:

  • Binary Search (sorted arrays)
  • First and last occurrence
  • Count frequency of target

Summary

Linear Search is the simplest and most intuitive searching technique. Although not optimal for large datasets, it is extremely effective for unsorted arrays and small input sizes. Understanding linear search is crucial before moving on to optimized searching algorithms.

Next Problem in the Series

Copy One Array into Another

Sanjiv
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